Reaction of R-CONH_2 with a mixture of Br_2 a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction described is the $Hofmann$ bromamide degradation reaction. The mechanism involves the following steps: $1$. Formation of $N$-bromamid

Vedclass · Accepted Answer

$A, C$

Vedclass · Answer

(C) The reaction described is the $Hofmann$ bromamide degradation reaction. The mechanism involves the following steps: $1$. Formation of $N$-bromamide: $R-CONH_2 + Br_2 + KOH \rightarrow R-CONHBr + KBr + H_2O$. $2$. Formation of an acyl nitrene or direct rearrangement: The $N$-bromamide reacts with base to form an anion,which loses $Br^-$ to form an acyl nitrene,which then rearranges to form an isocyanate intermediate: $R-CONHBr + KOH \rightarrow R-N=C=O + KBr + H_2O$. $3$. Hydrolysis of isocyanate: $R-N=C=O + 2KOH \rightarrow R-NH_2 + K_2CO_3$. Thus,the intermediates involved are $R-CONHBr$ $(A)$ and $R-N=C=O$ $(C)$.

Reaction of $R-CONH_2$ with a mixture of $Br_2$ and $KOH$ gives $R-NH_2$ as the main product. The intermediates involved in this reaction are :-
$(A)$ $R-CONHBr$
$(B)$ $R-NH-Br$
$(C)$ $R-N=C=O$
$(D)$ $R-CONBr_2$

Similar Questions

Which of the following amines reacts most rapidly with $CH_3I$?

For the given compounds:
$I$: Pyridine
$II$: Pyrrole
$III$: $3$-Pyrroline
$IV$: Guanidine
The correct statement is:

Identify the major product formed in the following reaction: $C_6H_5NH_2 + CHCl_3 + 3KOH \to ?$

Which of the following will give benzene when reacted with benzene diazonium chloride?

Identify $Y$ in the following reaction sequence:
$CH_3-CH(CH_3)-CH_2-CONH_2$ $\xrightarrow{KOBr(aq)} X$ $\xrightarrow{NaNO_2/HCl(aq)} Y$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Reaction of $R-CONH_2$ with a mixture of $Br_2$ and $KOH$ gives $R-NH_2$ as the main product. The intermediates involved in this reaction are :-$(A)$ $R-CONHBr$$(B)$ $R-NH-Br$$(C)$ $R-N=C=O$$(D)$ $R-CONBr_2$